6x^2+77x+240=0

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Solution for 6x^2+77x+240=0 equation:



6x^2+77x+240=0
a = 6; b = 77; c = +240;
Δ = b2-4ac
Δ = 772-4·6·240
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-13}{2*6}=\frac{-90}{12} =-7+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+13}{2*6}=\frac{-64}{12} =-5+1/3 $

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